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Welcome to our Physics lesson on Malus Law, this is the sixth lesson of our suite of physics lessons covering the topic of Polarization of Light, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
Non-polarized light can be considered as a continuous switch between p and s polarizations. If we take an ideal linear polarizer for simplicity, it is clear that such a polarizer will transmit only one type of polarization at a time. Therefore, the intensity of polarized light will be half of that of the original light. Thus, if we denote the initial intensity of unpolarised light by I0 and the intensity of polarized light by î(both measured in candela, [cd] which is one of the seven fundamental Sîunits), we obtain
To describe the relationship between polarized light I, unpolarised light I0 and the angle θ between the incident linear polarization and the polarization axis, we use the so-called Malus Law:
Calculate the light intensity of the polarized light if the parallel lines of the reflective linear polarizer used for this purpose form an angle of 300 to the electric vector of the incident light. Take the intensity of incident light equal to 20 cd, cos 300 = √3/2 and sin 300 = 1/2 if needed.
Applying the Malus Law
we obtain after substituting the values:
You have reached the end of Physics lesson 12.6.6 Malus Law. There are 6 lessons in this physics tutorial covering Polarization of Light, you can access all the lessons from this tutorial below.
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