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Welcome to our Physics lesson on Electrical to Mechanical Analogy between Two Oscillating Systems, this is the second lesson of our suite of physics lessons covering the topic of Alternating Current. LC Circuits, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
As stated earlier, an oscillating block and spring system represents a good analogy when trying to understand the behavior of quantities involved in a LC circuit, as both systems oscillate in a sinusoidal fashion. Thus, there are two types of energy involved in the block and spring system: one is kinetic (due to the block movement) and the other is (elastic) potential (stored in the spring). Neglecting the friction in the block and spring system and resistance in the LC circuit, we have
for the block and spring system and
for the LC circuit. The following table makes this point clearer.
From the above table, it is easy to deduce the following correspondences:
In Section 11 (more precisely in tutorial 11.2 "Energy in Simple Harmonic Motion"), we have seen that the general equation for the angular frequency ω of a SHM is
where T is the period of oscillation (i.e. the time needed to complete one oscillation). When applied for the mass and spring system, the equation of angular frequency becomes
where k is the spring constant and m is the mass of the attached object.
Substituting 1/C for k and L for m, we obtain for the angular frequency of a LC circuit:
Giving that
where f is the frequency of oscillations in Hertz, we obtain for the frequency of oscillations in a RL circuit (electrical frequency):
or
The value of electrical frequency in US, Canada, Brazil, Colombia, some regions in Japan and some small countries in Central America is 60Hz, while in the rest of the world, this frequency is 50 Hz. This means the current makes 50 or 60 complete cycles in one second when flowing through an AC circuit.
A LC circuit is operating somewhere in Europe. What is the capacitance of the capacitor if the inductance of the solenoid is 0.4 H?
Since the circuit is operating in Europe, the frequency of electricity must be 50 Hz. Therefore, giving that
we obtain for the capacitance C after raising both parts of the equation in power two to remove the root:
You have reached the end of Physics lesson 16.14.2 Electrical to Mechanical Analogy between Two Oscillating Systems. There are 5 lessons in this physics tutorial covering Alternating Current. LC Circuits, you can access all the lessons from this tutorial below.
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