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Welcome to our Physics lesson on Case 2 - Reference frame is moving at constant velocity and the object is at rest, this is the third lesson of our suite of physics lessons covering the topic of Relative Motion, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
This situation is similar to the one described in the Introduction (the moving car and the sideways trees). In this case, the object's velocity is v⃗ = 0 but the reference frame's velocity is v⃗'. If the reference frame is moving let's say due right (in the positive direction), the object seems moving due left (in the negative direction), although it is at rest.
If the object is initially at x⃗0, after t seconds, it will be at
Since the object is at rest (v⃗ = 0), the second term of the above equation is cancelled, so we obtain
where v⃗' is the velocity by which the reference frame is moving. Let's illustrate this point through a numerical example.
A car is moving at 20 m/s due right as shown in the figure.
What will the position of the tree in respect to the car be after 1.5 seconds?
Here the car acts as a reference frame. As stated before, the tree is at rest, so v⃗ = 0. Also, the car (which acts as a reference frame) is moving past the tree (it leaves the tree behind after a while). Therefore, the car's velocity is denoted as v⃗' = 20 m/s (it is positive as the car moves due right as well). Furthermore, the initial position of the tree is x⃗0 = 10 m as the tree initially is 10 m in front of the car. Therefore, we write
At t = 1.5 s we can write for the position of the tree x⃗:
This result means the tree is 20 m behind the car after 1.5 s of motion.
You have reach the end of Physics lesson 3.13.3 Case 2 - Reference frame is moving at constant velocity and the object is at rest. There are 7 lessons in this physics tutorial covering Relative Motion, you can access all the lessons from this tutorial below.
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