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Welcome to our Physics lesson on Case 5 - Reference point is moving at constant velocity and the object is moving at constant acceleration, this is the sixth lesson of our suite of physics lessons covering the topic of Relative Motion, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
In this case, the last term of the equation (3) is not cancelled but it is an active term of the equation. Thus, we have:
Factorizing, we obtain
Let's use the equation (3) or (4) (you can use whichever equation you wish as they are identical; it is up to your choice) to solve a numerical exercise.
A pedestrian initially at rest, starts walking at a⃗ = 0.5 m/s2 in the direction of a car when the car is 150 m away from him as shown in the figure.
The car itself is moving at 20 m/s in the direction of the pedestrian. What will the position of the pedestrian in respect to the car be after 10 seconds?
In this problem, we have the following clues:
Note 1. -0.5 m/s2 - the direction of motion is due left, i.e. a negative number
Using the equation (4), we obtain
Substituting the known values, we obtain
This means the pedestrian is 75 m behind the car after 10 s.
You have reach the end of Physics lesson 3.13.6 Case 5 - Reference point is moving at constant velocity and the object is moving at constant acceleration. There are 7 lessons in this physics tutorial covering Relative Motion, you can access all the lessons from this tutorial below.
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