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Welcome to our Physics lesson on Case 3 - Reference frame is moving at constant velocity and the object is moving at constant velocity, this is the fourth lesson of our suite of physics lessons covering the topic of Relative Motion, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
This is the case when two cars for example are moving either in the same or in the opposite direction. One of the cars is taken as a reference frame (for example the car in which we are inside) and the other car is considered as an object moving in respect to the first car. Once again, we use the equation (2) we discussed earlier
to find the position of the second object in respect to the first object (the reference frame).
Again, let's illustrate this point with a numerical example for a better understanding.
A car is moving due East at 15 m/s. A pedestrian who is initially 100 m in front of the car is walking at 2 m/s due West. What is the position of the pedestrian in respect to the car after 8s?
East is taken as positive direction and West as negative. Given this, we have the following clues:
Using the equation (2),
we obtain after the substitutions
This result means the man will be 36 m on the West (behind) the car after 8 seconds. Look at the figure:
You have reach the end of Physics lesson 3.13.4 Case 3 - Reference frame is moving at constant velocity and the object is moving at constant velocity. There are 7 lessons in this physics tutorial covering Relative Motion, you can access all the lessons from this tutorial below.
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