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Welcome to our Physics lesson on Effective Values of Alternating Current and Voltage, this is the fifth lesson of our suite of physics lessons covering the topic of The Series RLC Circuit, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
Effective Values of Alternating Current and Voltage
From all discussed so far about the current and voltage in an alternating circuit, we can point out two important features:
- Both the current and voltage oscillate in a sinusoidal fashion
- Current and voltage can be either positive or negative
If we are asked to find other related quantities in an AC circuit such as power or energy, we cannot use the maximum values of current and voltage as this gives a considerable error; all values would be higher than actually they are. We cannot consider other known methods to find the average values such as the arithmetic mean, or approximations of the sinusoids to obtain a series or rectangles for example. Therefore, the only available method remains the root mean square method, similar to that discussed in the kinetic theory of gases, in which we calculated the rms speed of an ideal gas molecule.
Giving that
i(t) = imax ∙ sin(ωd ∙ t)
we obtain for the rms current
irms = √[imax ∙ sin(ωd ∙ t) ]2ave
= √i2max ∙ sin2 (ωd ∙ t)ave
Since from trigonometry it is known that
sin2 (ωd ∙ t)ave = 1/2
we can write
irms = √i2max ∙ 1/2
irms = imax ∙ √1/2
= imax ∙ 1/r = √2
= imax/√2
≈ 0.707 ∙ imax
Thus,
iave = irms = imax/√2
We have used this value earlier in some exercises but now you know what does it mean.
Likewise, for the average voltage, we have
∆Vave = ∆Vrms = irms ∙ R
= imax/√2 ∙ R
= ∆Vmax/√2
Example 3
A series RLC circuit is shown in the figure.
Calculate:
- The resonance frequency of the circuit
- The root mean square of current when the circuit is in resonance
- The maximum voltages across the resistor, inductor and capacitor when the circuit is in resonance
Solution 3
We have
εmax = 250 V
R = 5 Ω
L = 5 mH = 5 × 10-3 H
C = 4 μF = 4 × 10-6 F
- The resonance frequency of the circuit is obtained when XL - XC = 0 or when XL = XC. Thus, we have
XL = Xc
ωd ∙ L = 1/ωd ∙ C
ωd2 = 1/L ∙ C
2π ∙ f = 1/√L ∙ C
f = 1/2π ∙ √L ∙ C
= 1/2 ∙ 3.14 ∙ √(5 × 10-3 ) ∙ (4 ∙ 10-6 )
= 1/6.28 ∙ √2 ∙ 10-8
= 1/6.28 ∙ 1.414 × 10-4
= 1126 Hz
- First, let's calculate the impedance in the circuit. If the circuit is in resonance, we have
Z = √R2 + (XL - Xc )2
= √R2 + 02
= √R2
= R
= 5 Ω
The maximum current in the circuit therefore is imax = εmax/Z
= 250 V/5 Ω
= 50 A
Hence, the rms current in the circuit is irms = imax/√2
= 50 A/1.414
= 35.4 A
- The maximum voltages in each component of the circuit are
ΔVR(max) = imax ∙ R
= (50 A) ∙ (5Ω)
= 250 V
ΔVL(max) = imax ∙ XL
= imax ∙ 2πf ∙ L
= (50 A) ∙ (2 ∙ 3.14 ∙ 1126 ∙ 0.005 Ω)
= 1768 V
ΔVC(max) = imax ∙ Xc
= imax ∙ 1/2πf ∙ C
= (50 A) ∙ (1/2 ∙ 3.14 ∙ 1126 ∙ (4 × 10-6 ) )
= 1768 V
You have reached the end of Physics lesson 16.16.5 Effective Values of Alternating Current and Voltage. There are 5 lessons in this physics tutorial covering The Series RLC Circuit, you can access all the lessons from this tutorial below.
More The Series RLC Circuit Lessons and Learning Resources
Magnetism Learning MaterialTutorial ID | Physics Tutorial Title | Tutorial | Video Tutorial | Revision Notes | Revision Questions |
---|
16.16 | The Series RLC Circuit | | | | |
Lesson ID | Physics Lesson Title | Lesson | Video Lesson |
---|
16.16.1 | Recap on the Series RLC Circuit | | |
16.16.2 | The Current Amplitude | | |
16.16.3 | The Phase Constant | | |
16.16.4 | Resonance in a Series RLC Circuit | | |
16.16.5 | Effective Values of Alternating Current and Voltage | | |
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