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Welcome to our Physics lesson on Applications of cross product in Physics, this is the fifth lesson of our suite of physics lessons covering the topic of Vector Product of Two Vectors, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
In Physics, there are a lot of applications of vector cross product. They are much more than dot product applications. Let's discuss briefly some of them.
1. Moment of force M⃗ as cross product of Force F⃗ and linear distance from the turning point Δx⃗
It is obvious Moment of force is a vector quantity as unlike Work, it is obtained through the cross product of Force and Linear distance from the turning point.
2. Magnetic force F⃗ of a conductor at rest as a cross product of Magnetic induction B⃗ and the conductor length L⃗ multiplied with the scalar I (current).
3. Magnetic force F⃗ of a moving conductor as a cross product of Magnetic induction B⃗ and Velocity v⃗ multiplied with the scalar q (electric charge).
4. The angle between two forces F⃗1 and F⃗2 can be calculated using the cross product if the magnitudes of the two vectors F⃗1 and F⃗2 and that of F⃗1 × F⃗2 are known,
and so on.
A conducting wire is placed between the two poles of a horseshoe magnet as shown in the figure. The magnetic field lines (the induction B⃗) lie from the North to the South pole of the magnet. Electric charges flow through the conducting wire in a direction that is away from us (from us to the sheet). To make the reader have a better idea, the figure is slightly inclined.
If the magnitude of the magnetic induction is b⃗ = 4 Tesla (B⃗ = 4 T) and the amount of electric charges flowing through the wire is q = 6 Coulombs (q = 6 C), find the velocity v⃗ of wire (both magnitude and direction) if it forms a right angle to the magnetic field lines. The magnetic force produced is F⃗ = 0.2N
.From the figure, it is easy to see that we move clockwise from q-direction to B-direction. Therefore, if you consider the wire as the handle of a screwdriver, and giving that you are rotating it clockwise, the screw will move forward. Thus, in this case, the wire will move due left.
Also, from the clues, it is obvious that the wire is perpendicular to the magnetic field lines. This means sin θ = sin 900 = 1.
The magnitude of velocity is calculated by the equation
From the cross product rules, we have
Substituting the known values, we obtain (giving that sin 90° = 1)
You have reach the end of Physics lesson 2.5.5 Applications of cross product in Physics. There are 6 lessons in this physics tutorial covering Vector Product of Two Vectors, you can access all the lessons from this tutorial below.
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