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Physics Lesson 2.5.5 - Applications of cross product in Physics

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Welcome to our Physics lesson on Applications of cross product in Physics, this is the fifth lesson of our suite of physics lessons covering the topic of Vector Product of Two Vectors, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Applications of cross product in Physics

In Physics, there are a lot of applications of vector cross product. They are much more than dot product applications. Let's discuss briefly some of them.

1. Moment of force M as cross product of Force F and linear distance from the turning point Δx

The formula of Moment of force therefore is:

M = F × Δx

It is obvious Moment of force is a vector quantity as unlike Work, it is obtained through the cross product of Force and Linear distance from the turning point.

2. Magnetic force F of a conductor at rest as a cross product of Magnetic induction B and the conductor length L multiplied with the scalar I (current).

The formula of Magnetic force therefore is

F = I × (B × L)

3. Magnetic force F of a moving conductor as a cross product of Magnetic induction B and Velocity v multiplied with the scalar q (electric charge).

The formula of Magnetic force in this case is

F = q × (B × v)

4. The angle between two forces F1 and F2 can be calculated using the cross product if the magnitudes of the two vectors F1 and F2 and that of F1 × F2 are known,

and so on.

Example

A conducting wire is placed between the two poles of a horseshoe magnet as shown in the figure. The magnetic field lines (the induction B) lie from the North to the South pole of the magnet. Electric charges flow through the conducting wire in a direction that is away from us (from us to the sheet). To make the reader have a better idea, the figure is slightly inclined.

Physics Tutorials: This image shows vectors plotted on a graph with a parallelogram

If the magnitude of the magnetic induction is b = 4 Tesla (B = 4 T) and the amount of electric charges flowing through the wire is q = 6 Coulombs (q = 6 C), find the velocity v of wire (both magnitude and direction) if it forms a right angle to the magnetic field lines. The magnetic force produced is F = 0.2N

.

Solution

From the figure, it is easy to see that we move clockwise from q-direction to B-direction. Therefore, if you consider the wire as the handle of a screwdriver, and giving that you are rotating it clockwise, the screw will move forward. Thus, in this case, the wire will move due left.

Also, from the clues, it is obvious that the wire is perpendicular to the magnetic field lines. This means sin θ = sin 900 = 1. Physics Tutorials: This image shows a vector of magnetic induction within a horseshoe magnet

The magnitude of velocity is calculated by the equation

F = q × (B × v)

From the cross product rules, we have

|F| = q × |B| × |v| × sin90°

Substituting the known values, we obtain (giving that sin 90° = 1)

0.2N = 6 C × 4 T × |v| × 1
|v| = 0.2N/6 C × 4 T
= 1/120 m/s
= 0.0083 m/s

You have reach the end of Physics lesson 2.5.5 Applications of cross product in Physics. There are 6 lessons in this physics tutorial covering Vector Product of Two Vectors, you can access all the lessons from this tutorial below.

More Vector Product of Two Vectors Lessons and Learning Resources

Vectors and Scalars Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
2.5Vector Product of Two Vectors
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
2.5.1The meaning of cross product of vectors multiplication
2.5.2How to calculate the cross product of two vectors?
2.5.3What is the direction of the vector product obtained by the cross product of two vectors?
2.5.4Cross product of vectors in coordinates
2.5.5Applications of cross product in Physics
2.5.6Mixed product of vectors

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