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Physics Lesson 2.4.1 - How to calculate the dot (scalar) product of two vectors

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Welcome to our Physics lesson on How to calculate the dot (scalar) product of two vectors, this is the first lesson of our suite of physics lessons covering the topic of Dot (Scalar) Product of Two Vectors, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

How to calculate the dot (scalar) product of two vectors

If we appoint a basic direction (for example Ox) to the first vector a, we write as bx instead of b||a the component of the vector b in the direction of a. It is obvious the component of vector b perpendicular to a is denoted as by instead of b⊥a.

Also, we can appoint a letter (for example θ) to the acute angle formed by the vector a (or its extension) and the vector b. Therefore, the above figure is written as:

Physics Tutorials: This image shows 2 vectors to help illustrate how to calculate a dot scalar of two products

The component by is equal in length to the opposite side to the angle θ for the triangle shown in the figure. Therefore, we can "close" this triangle to form a right triangle as shown below.

Physics Tutorials: This image contains a rounded corner box placed on a surface to illustrate the calculation of mechanical power in physics

From trigonometry, it is known that in a right triangle (as the one shown in the above figure), we have

bx = |b| ∙ cos θ

and

by = |b| ∙ sin θ

Therefore, for the dot (scalar) product of the vectors a and b we can write:

a ∙ b = |a | ∙ |bx |
=|a | ∙ |b | ∙ cos θ

It is obvious the above product represents a scalar (number) c, not a vector, because we found it by multiplying two vector magnitudes (which are simply numbers) and the cosine of an angle (which is a number as well). Hence, if we denote by c the dot product of two vectors a and b, we obtain

c = |a| ∙ |b| ∙ cos θ

Example 1

Mechanical Power P in Physics is alternatively defined as the dot product of force F exerted on an object and the velocity v gained by the object due to the action of this force.

A 120 N force acts at an object at 200 to the horizontal direction as shown in the figure. As a result, the object moves at constant velocity by a magnitude of 0.4 m/s. Calculate the useful power delivered by the source in Watts (1 Watt = 1 Joule ∙ second). Take cos 200 = 0.94, sin 200 = 0.34.

Physics Tutorials: This image contains a grid with vectors u and v identified to support the physics tutorial on dot vectors

Solution 1

As stated above, by definition, Power is the scalar product of Force and Velocity. From the mathematical definition of the scalar product of two vectors, we know that to find the dot product of two vectors, we must multiply one vector with the component of the other vector in the direction of the first one. In the specific case, the movement occurs in the direction of the velocity vector. Therefore, we take the velocity vector as the first one and express the direction of force vector in terms of it. Thus, we must multiply in scalar mode the velocity vector v and the component of force F according to the direction of v. This means we have to calculate:

P = v ∙ F
=|v | ∙ |Fn the direction of v |
=|v | ∙ F ∙ cos θ

After substituting the values, we obtain

P = 0.4 m/s ∙ 120N ∙ 0.94
= 45.12 Watt

Another method for calculating the dot product of two vectors. Calculating the dot product using coordinates

If the coordinates of the two vectors are known, it is much easier to calculate their dot product. We don't need to know the angle in-between or the magnitudes of the vectors. We can use the formula:

a ∙ b = xa ∙ xb + ya ∙ yb

This formula is particularly useful when none of vectors lies according to a main direction (axis). Thus, instead of trying to calculate the angle in-between by finding the difference of two angles (the angle formed by the vector u to the horizontal axis minus the angle formed by the vector v to the horizontal axis) (look at the figure below), and then expressing the direction of the second vector in terms of the first one, it is much easier multiplying only the coordinates as no angle is needed here.

Physics Tutorials: This image contains a grid with vectors u and v identified to support the physics tutorial on dot vectors

For simplicity, both vectors are taken with their origin (tail) at (0, 0). The procedure to calculate the angle between the two vectors is quite long. First, we need to find the angles formed by each vector to the horizontal direction by considering the tangents (y-coordinate / x-coordinate). After finding each tangent, we find the respective angles using a scientific calculator. Afterwards, we subtract the angles to find the angle between the two vectors. Finally, we can use the (first) dot product formula to find the result. As you see, it is not worth trying it.

By using the new formula of dot product, we find the result in a much easier way. Thus, from the figure you can find all coordinates you need. They are: xu = 7 units, xv = 13 units, yu = 10 units and yv = 4 units.

Substituting the above values, we obtain

u ∙ v = xu ∙ xv + yu ∙ yv
= (7 ∙ 13 + 10 ∙ 4) units
= (91 + 40) units
= 131 units

You have reach the end of Physics lesson 2.4.1 How to calculate the dot (scalar) product of two vectors. There are 2 lessons in this physics tutorial covering Dot (Scalar) Product of Two Vectors, you can access all the lessons from this tutorial below.

More Dot (Scalar) Product of Two Vectors Lessons and Learning Resources

Vectors and Scalars Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
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Revision
Notes
Revision
Questions
2.4Dot (Scalar) Product of Two Vectors
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
2.4.1How to calculate the dot (scalar) product of two vectors
2.4.2Dot (scalar) product applications in Physics

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