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Physics Lesson 2.4.2 - Dot (scalar) product applications in Physics

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Welcome to our Physics lesson on Dot (scalar) product applications in Physics, this is the second lesson of our suite of physics lessons covering the topic of Dot (Scalar) Product of Two Vectors, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Dot (scalar) product applications in Physics

There are many applications of dot (scalar) product of two vectors in Physics. Below, we will mention only a few of them.

1. Work as a dot product of Force and Displacement.

We have discussed earlier (in Introduction) this point. If you multiply in scalar mode the force exerted by an object and the displacement of the object due to the action of this force, the result will be a scalar quantity known as Work and measured in Joules. It is meaningless to say "the work done by the force F is 300 J due East" for example. We simply say "the work done by the force F is 300 J" as work is a quantity related to the change in energy of a system (see the article 5.1 "Work and Energy" for more detail); it does not involve any direction.

2. Power as a dot product of Force and Velocity.

We discussed this point earlier in the solved example. If we multiply in scalar mode the two vector quantities, Force and Displacement, we obtain a scalar result that is Power. It does not involve any direction as well.

3. The angle between two forces acting on the same object.

Let's consider again the solved example in the previous section (let's take the abovementioned vectors as force vectors and the units as newtons).

Physics Tutorials: This image contains a grid with vectors u and v identified to support the physics tutorial on dot vectors

We found the dot product of vectors u and v and it was 131 units. Now, let's calculate the magnitudes of each vector. From the article "Vectors and Scalars in Physics" we know that

|u|= √u2x + u2y = √72 + 102 = √49 + 100 = √149 units

and

|v| = √v2x + v2y = √132 + 42 = √169 + 16 = √185 units

Therefore, we obtain for the angle between u and v

u ∙ v = |u| ∙ |v| ∙ cos (∡ u,v)
cos (∡ u,v) = u ∙ v/|u| ∙ |v|
= 131/149 ∙ √185
= 131/166
= 0.789

Therefore, the angle between the two vectors u and v is cos-1 0.789 = 37.890.

This result was obtained much easier than if we used the (long) method described in the previous section.

4. Kinetic Energy as a dot product of linear momentum and velocity.

Kinetic Energy of a moving object (a scalar quantity measured in Joules like Work) is calculated through the equation

KE = 1/2 ∙ m ∙ v2

where m is the mass of the object and v is its velocity (look at the article "Kinetic Energy. Work-Kinetic Energy Theorem" for more info regarding this concept).

However, since the linear momentum of a moving object is p = m ∙ v (look at the article "Momentum and Impulse" for more info regarding this concept), we obtain for the kinetic energy KE

KE = 1/2 ∙ (m ∙ v ) ∙ v
= 1/2 ∙ p ∙ v

Therefore, Kinetic Energy can be expressed as the dot product of two vectors, p and v multiplied by a constant 1/2 (which only changes the result; it does not breaks the abovementioned rule).

These were some examples showing the most important applications of dot product in Physics.

You have reach the end of Physics lesson 2.4.2 Dot (scalar) product applications in Physics. There are 2 lessons in this physics tutorial covering Dot (Scalar) Product of Two Vectors, you can access all the lessons from this tutorial below.

More Dot (Scalar) Product of Two Vectors Lessons and Learning Resources

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2.4Dot (Scalar) Product of Two Vectors
Lesson IDPhysics Lesson TitleLessonVideo
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2.4.1How to calculate the dot (scalar) product of two vectors
2.4.2Dot (scalar) product applications in Physics

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