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Welcome to our Physics lesson on **Induced Current**, this is the fourth lesson of our suite of physics lessons covering the topic of **Induction and Energy Transfers**, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

We can still apply the Ohm's Law

i = *ε*_{i}*/**R*

to calculate the current induced in the loop if the resistance of coil is known. Combining this law with the equation

ε_{i} = B ∙ w ∙ v

provided in the previous paragraph, we obtain for the induced current I:

i = *B ∙ w ∙ v**/**R*

Giving that the magnetic force produced in a current carrying wire is

F_{M} = i ∙ B ∙ L

where L is the length of wire (do not confuse it with the inductance explained in the previous tutorial), we obtain for the specific setup discussed in this tutorial where the length of the metal bar L here is represented by the width w of the rectangular coil:

F_{M} = i ∙ B ∙ w

This is true because there is no magnetic force in the direction of the two long sides of the coil but only in the direction of the lateral ones. The only forces acting on the coil are the pulling force (due right) and the magnetic force (due left) which are balanced as the coil moves at constant velocity. Therefore, we obtain for the magnetic force acting on the loop:

F_{M} = (*B ∙ w ∙ v**/**R*) ∙ B ∙ w

=*B*^{2} ∙ w^{2} ∙ v*/**R*

=

From the last equation, we conclude that if the magnetic force F_{m} is constant, the moving speed v of the coil is constant as well. This is because the other parameters such as the magnetic field B, the width of loop w and the resistance R are all constants.

You have reached the end of Physics lesson **16.10.4 Induced Current**. There are 6 lessons in this physics tutorial covering **Induction and Energy Transfers**, you can access all the lessons from this tutorial below.

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