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Physics Lesson 16.7.3 - Induced Electromotive Force as Motional Emf

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Welcome to our Physics lesson on Induced Electromotive Force as Motional Emf, this is the third lesson of our suite of physics lessons covering the topic of Faraday's Law of Induction, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Induced Electromotive Force as Motional Emf

Let's extend the discussion about the induced emf considering it from another viewpoint. As a special case of electromagnetic induction is when a magnetic force acts on a straight current carrying wire placed inside a uniform magnetic field is moving due right as shown in the figure below.

Physics Tutorials: This image provides visual information for the physics tutorial Faraday's Law of Induction

The direction of the resulting magnetic force is vertically down, based on the Fleming's Left Hand Rule explained in the previous tutorials. The scalar equation of this magnetic force is

FM = Q ∙ v ∙ B

Since the wire is moving due right, the magnetic force is balanced by another force acting in the upward direction. This force is the electric force Fe produced on the moving charges.

Physics Tutorials: This image provides visual information for the physics tutorial Faraday's Law of Induction

We can write the equation that shows mathematically this balance of forces as

FM = Fe
Q ∙ v ∙ B = Q ∙ E
E = v ∙ B

Since the electric field produced by the moving charges is constant, we express the relationship between the electric field E and the potential difference ΔV across the ends of conducting wire as

∆V = E ∙ L

Combining the last two equation, we obtain

∆V = B ∙ L ∙ v

This potential difference is equal to the emf ε of the wire as the resistance of wire is negligible. Obviously, this is an induced emf as it is caused due to the motion of wire and is not constant; it depends on the following factors:

  1. Magnitude of magnetic field - a stronger field causes a higher induced emf than a weaker magnetic field;
  2. Length of conductor - a longer conductor causes a higher induced emf than a shorter one;
  3. Velocity of conductor - a greater velocity causes a higher induced emf in the wire than a lower velocity.
    Another factor that affects the induced emf produced in the wire is the angle between the moving direction and the wire itself. So far, we have considered only the case in which the moving direction is perpendicular to the wire's length. In this case, the induced emf is maximal. However, when we push the wire in another direction, the potential difference decreases until it becomes zero when the wire is pushed in the direction of its length. Hence, we write the fourth factor affecting the amount of induced emf as
  4. The angle formed by the wire and its moving direction.
Physics Tutorials: This image provides visual information for the physics tutorial Faraday's Law of Induction

Hence, the formula of emf induced in the conducting wire when it moves inside a magnetic field is

εi = B ∙ v ∙ L ∙ sin⁡θ

If the conductor that is sliding due right is part of a closed conducting path as shown in the figure below,

Physics Tutorials: This image provides visual information for the physics tutorial Faraday's Law of Induction

then, electrons will move in the clockwise direction throughout the circuit due to the existence of emf produced by the source. (Remember the direction of conventional current is opposite to the direction of electron's flow).

The value of current I flowing through the circuit in this case, is

I = εi/R = B ∙ v ∙ L/R

where R is the resistance in the circuit.

Example 2

At what speed should we move a 50 cm bar as shown in the figure below to produce a current of 0.4 A if the bar touches the two opposite sides of a circuit having a resistance of 20 Ω? The plane of circuit (including the bar) is normal to a 2 T magnetic field the direction of which is into the page.

Physics Tutorials: This image provides visual information for the physics tutorial Faraday's Law of Induction

Solution 2

Clues:

L = 50 cm = 0.50 m
I = 0.4 A
R = 20 Ω
B = 2 T
v = ?

From the equation

I = ε/R = B ∙ v ∙ L/R

we obtain for the speed v after rearranging the terms

v = I ∙ R/B ∙ L
= (0.4 A) ∙ (20 Ω)/(2 T) ∙ (0.50 m)
= 8 m/s

You have reached the end of Physics lesson 16.7.3 Induced Electromotive Force as Motional Emf. There are 4 lessons in this physics tutorial covering Faraday's Law of Induction, you can access all the lessons from this tutorial below.

More Faraday's Law of Induction Lessons and Learning Resources

Magnetism Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
16.7Faraday's Law of Induction
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
16.7.1What did Faraday Observe during His Experiments?
16.7.2Faraday's Law of Induction
16.7.3Induced Electromotive Force as Motional Emf
16.7.4Motional Emf and Electrical Energy

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