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Physics Lesson 2.3.1 - Multiplying a vector by a positive scalar

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Welcome to our Physics lesson on Multiplying a vector by a positive scalar, this is the first lesson of our suite of physics lessons covering the topic of Multiplication of a Vector by a Scalar, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Multiplying a vector by a positive scalar

The similarity rule discussed in the "Introduction" section is applied in all the other fields of science as well. Vectors do not make any exception in this regard. Therefore, if we want to multiply a vector by a positive scalar, the result will be a new vector whose characteristics (direction, unit, the physical quantity they represent etc.) are all similar to the original vector except length. Thus, if we read in a certain passage that CD = 3 × AB we understand three things:

  1. Vectors AB and CD have the same direction (they are parallel or collinear)
  2. Not always they represent the same type of physical quantity. It only occurs when the scalar has no unit (we will discuss this point in the solved example shown below). However, in this case the scalar 3 has no unit. Thus, here both vectors are measured with the same unit
  3. The vector CD is triple in length the vector AB

The figure below shows an illustration of this example.

Physics Tutorials: This image shows

From the figure, you can see that both vectors have the same direction, as they are parallel. However, the length of the vector CD is triple of the length of AB as CD is 9 units long and AB is 3 units long. Hence, we can write

CD = 3 × AB

We can generalize this rule by writing:

If a vector u is parallel to another vector v and the length of u is N times greater than the length of v, then

u = N × v

where N is a number (scalar).

Example 1

A ship can carry a maximum of 20,000,000 N load when floating on pure water (on a lake). What is the extra load (in newtons) the same ship can carry if it is floating on salty water? Take the densities of pure and salty water equal to 1000 kg/m3 and 1030 kg/m3 respectively. For simplicity, take the gravitational field strength g ≈ 10 N/kg. The equation used to calculate the buoyant (lifting) force of water is F = ρ × g × V where V is the volume of the ship immersed in water and ρ is the density of water.

Solution 1

Since the ship is floating on water its weight is balanced by the buoyant (lifting) force of water. Density and volume of water are both scalar quantities. Only gravity (gravitational field strength) and buoyant force are vectors. Therefore, this is a typical example of multiplication of a vector by a scalar (where the result is a vector).

Physics Tutorials: This image shows

First, let's calculate the volume of the ship. Thus, for the ship floating on pure water we have

Fpure water × g × Vship
Vship= F/ρpure water × g= 20,000,000N/1000 kg/m3 × 10 N/kg = 2000 m3

Since there is the same ship in both cases (the volume is the same therefore), when it floats on salty water, we have

Loadmax = Fnew = ρsalty water × g × V
= 1030 kg/m3 × 10 × N/kg × 2000 m3
= 20,600,000 N

Therefore, the ship can hold 20,600,000N - 20,000,000N = 600,000N more load than when it is floating on pure water.

You have reach the end of Physics lesson 2.3.1 Multiplying a vector by a positive scalar. There are 4 lessons in this physics tutorial covering Multiplication of a Vector by a Scalar, you can access all the lessons from this tutorial below.

More Multiplication of a Vector by a Scalar Lessons and Learning Resources

Vectors and Scalars Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
2.3Multiplication of a Vector by a Scalar
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
2.3.1Multiplying a vector by a positive scalar
2.3.2Division of a vector by a scalar as multiplication with the inverse
2.3.3Multiplying a vector by a negative scalar
2.3.4How to multiply a vector by a scalar in coordinates?

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