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Welcome to our Physics lesson on The Relationship between Potential Difference and Electric Field, this is the fifth lesson of our suite of physics lessons covering the topic of Electric Potential, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
In the last two tutorials, we assumed the electric field between two parallel plates charged at opposite sign as uniform, especially when the distance d between the plates is small. As stated earlier, when we place a positive charge Q to the positive plate, its potential energy is at maximum. Thus,
For convenience, we can assume the potential at the negative plate as zero. As a result, the charge's potential energy at the negative plate is zero as well.
We know that the potential difference is
If expressed in terms of E, the last formula becomes
From the above formula, we obtain the SI unit of electric field, which is Volt/metre [V/m], as the potential difference is measured in volts and distance in metres. Remember, in the previous tutorial we used another unit form electric field: Newton per Coulomb [N/C]. Hence, we can write
The reason why the standard unit of electric field is V/m and not N/C is because V/m contains one fundamental SI unit (metre), while neither Newton nor Coulomb are fundamental SI units.
The formula E = ΔV / d expresses how large the potential difference in the unit of charge must be in order to produce a given electric field. Thus, if in a given region the electric field is zero, the potential in that region does not change (is constant).
Electric potential decreases when we move in the direction of electric field. Thus, for a point charge as the one shown in the figure, we have V1 > V2 > V3.
You have reached the end of Physics lesson 14.5.5 The Relationship between Potential Difference and Electric Field. There are 8 lessons in this physics tutorial covering Electric Potential, you can access all the lessons from this tutorial below.
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