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Physics Lesson 9.5.4 - Buoyancy in Gases

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Welcome to our Physics lesson on Buoyancy in Gases, this is the fourth lesson of our suite of physics lessons covering the topic of Buoyancy. Archimedes' Principle, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Buoyancy in Gases

We can say the same words for buoyancy in gases as well. The only difference is that in gases there is no floating; we consider the object completely immersed in gas (especially in air). The third case mentioned above when buoyancy in liquids was explain (i.e. when density of object is smaller than the density of gas), is discussed only to see whether the object is moving up or not. Thus, the three cases explained in the buoyancy of liquids adapted for buoyancy in gases are:

  1. When Fb < Wobject the object falls down on the ground. In this case, ρgas < ρobject
  2. When Fb = Wobject the object stays unmoveable, suspended in gas. In this case, ρgas = ρobject
  3. When Fb > Wobject the object rises up. In this case, ρgas > ρobject

Example 4

A balloon weighs 12 000 N when empty (all people and equipment are included in this value). When the balloon is flying, it has a volume of 1500 m3. What is happening with the balloon (is it rising up, saying unmoveable in air or falling down) if the balloon is filled with hot air (ρhot air = 0.8 kg/m3) and f the surrounding (cold) air has a density of 1.3 kg/m3? Take g = 10 m/s2.

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Solution 4

The solution is simple. We must calculate the buoyant force caused by the cold air and compare it with the weight of empty balloon plus the weight of hot air inside the balloon. We have:

Fb (cold air) = ρcold air × Vballoon × g
= 1.3 × 1500 × 10
= 19 500 N

Weight of the hot air inside the balloon is

Whot air = mhot air × g
= ρhot air × Vballoon × g
= 0.8 × 1500 × 10
= 12 000 N

Therefore, the total downward force is

Fdown = Wempty balloon + Whot air
= 12 000 N + 12 000 N
= 24 000 N

Since this force is greater than the buoyant force (lifting force) of the surrounding (cold) air, (24 000 N > 19 500 N), the balloon is falling down at 24 000 N - 19 500 N = 4500 N of resultant force.

You have reached the end of Physics lesson 9.5.4 Buoyancy in Gases. There are 4 lessons in this physics tutorial covering Buoyancy. Archimedes' Principle, you can access all the lessons from this tutorial below.

More Buoyancy. Archimedes' Principle Lessons and Learning Resources

Density and Pressure Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
9.5Buoyancy. Archimedes' Principle
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
9.5.1What is Buoyancy?
9.5.2Buoyant Force
9.5.3Archimedes' Principle
9.5.4Buoyancy in Gases

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