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Physics Lesson 22.2.10 - Day and Night

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Welcome to our Physics lesson on Day and Night, this is the tenth lesson of our suite of physics lessons covering the topic of Sun and Planetary Motion, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

Day and Night

"Day" represents the time in which a region of Earth is directly exposed to sunrays. Night is the opposite, i.e. a region is either illuminated indirectly from the Sun (through Moon surface that reflects the sunrays on Earth) or by means of other light sources (usually artificial, such as electric bulbs).

All locations on the equatoralways have equal durations of day and night as the sunlight always falls on them at the same angle. On the other hand, the further North (or South for southern hemisphere) a location is, the more variation there is between day and night duration at solstice(s). For example, in locations near the North Pole, no sunset occurs for several months during summer solstice while the sun does not rise for several months (during winter solstice) on locations near the South Pole in the same period of year.

Example 3

A certain location receives 1400 W/m2 energy during the summer solstice, where the angle of incidence is normal to the ground. How much solar energy per unit area does the same location receive in winter solstice if the deflection angle to the vertical in that moment is 72° (cos 72° = 0.309, sin 72° = 0.951).

Solution 3

We denote by E0 the maximum energy falling in the given location (E0 = 1400 W/m2). When sunrays fall normal to the ground, the effect of energy transfer is at its' maximum. Thus, if we consider the incidence angle as 0° to the normal, we must multiply the value of energy by cos 0°, as this gives the maximum value (cos 0° = 1). When the angle of incidence becomes 72°, we must therefore multiply the previous value of energy by cos 72° to find the amount of solar energy falling on that location in winter. Hence, we have

E = E0 ∙ cos⁡720
= 1400 W/m2 ∙ 0.309
= 432.6 W/m2

You have reached the end of Physics lesson 22.2.10 Day and Night. There are 10 lessons in this physics tutorial covering Sun and Planetary Motion, you can access all the lessons from this tutorial below.

More Sun and Planetary Motion Lessons and Learning Resources

Cosmology Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
22.2Sun and Planetary Motion
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
22.2.1Basic Features
22.2.2The Source of Solar Energy
22.2.3Energy Transmission from Core to Surface of the Sun
22.2.4Structure of the Sun
22.2.5Planetary Motion around the Sun
22.2.6Observation of Planetary Motion from Earth
22.2.7Planetary Rotation around Own Axis
22.2.8Earth Rotation around its Own Axis
22.2.9Seasons
22.2.10Day and Night

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  1. Day Night Feedback. Helps other - Leave a rating for this day night (see below)
  2. Cosmology Physics tutorial: Sun and Planetary Motion. Read the Sun and Planetary Motion physics tutorial and build your physics knowledge of Cosmology
  3. Cosmology Revision Notes: Sun and Planetary Motion. Print the notes so you can revise the key points covered in the physics tutorial for Sun and Planetary Motion
  4. Cosmology Practice Questions: Sun and Planetary Motion. Test and improve your knowledge of Sun and Planetary Motion with example questins and answers
  5. Check your calculations for Cosmology questions with our excellent Cosmology calculators which contain full equations and calculations clearly displayed line by line. See the Cosmology Calculators by iCalculator™ below.
  6. Continuing learning cosmology - read our next physics tutorial: The Moon's Movement. Eclipses. Calendars

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