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Welcome to our Physics lesson on What happens if the acting force is not normal to the bar?, this is the second lesson of our suite of physics lessons covering the topic of Moment of Force. Conditions of Equilibrium, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.
What happens if the acting force is not normal to the bar?
In this case, we consider only the force component that lies normal to the bar as only it contributes in the rotation of the system. The other component, i.e. the component of force according the direction of the bar, goes in vain, as it gives no contribution in the rotation. Look at the example below:
Example 2
How far from the bar is the application point of the force F in the system shown in the figure below? Take g = 10 N/kg, cos 530 = 0.6 and sin 530 = 0.8.
Solution 2
Let's use a scalar approach to solve this problem. We have the following clues:
m = 4 kg
Δx1 = d1 = 1.2 m
F2 = 60 N
d2 = ?
Let's find some missing quantities first. Thus,
F1 = W = m × g
= 5 kg × 10 N/kg
= 50 N
F2x = F2 × cos 530
= 60 N × 0.6
= 36 N
F2y = F2⊥ = F2 × sin 530
= 60 N × 0.8
= 48 N
Thus, we have
F1⊥ × d1 = F2⊥ × d2
After substitution, we obtain
40 × 1.2 = 48 × d2
48 = 48 × d2
d2 = 48/48 = 1m
You have reached the end of Physics lesson 6.4.2 What happens if the acting force is not normal to the bar?. There are 7 lessons in this physics tutorial covering Moment of Force. Conditions of Equilibrium, you can access all the lessons from this tutorial below.
More Moment of Force. Conditions of Equilibrium Lessons and Learning Resources
Centre of Mass and Linear Momentum Learning MaterialTutorial ID | Physics Tutorial Title | Tutorial | Video Tutorial | Revision Notes | Revision Questions |
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6.4 | Moment of Force. Conditions of Equilibrium | | | | |
Lesson ID | Physics Lesson Title | Lesson | Video Lesson |
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6.4.1 | What is Moment of Force? | | |
6.4.2 | What happens if the acting force is not normal to the bar? | | |
6.4.3 | What happens if more than two forces are acting on a turning system? | | |
6.4.4 | What happens if there is no equilibrium in a turning system? | | |
6.4.5 | What if the bar is heavy and as such, we cannot neglect its weight? | | |
6.4.6 | What if the bar is hanged on a string? | | |
6.4.7 | Conditions of Equilibrium | | |
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