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Physics Lesson 5.1.4 - The graphical representation of Work

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Welcome to our Physics lesson on The graphical representation of Work, this is the fourth lesson of our suite of physics lessons covering the topic of Work and Energy. Types of Energy, you can find links to the other lessons within this tutorial and access additional physics learning resources below this lesson.

The graphical representation of Work

First, let's consider a constant force F newtons acting on an object. As a result, the object moves horizontally by Δx meters. If we take the initial position xi = 0, the final position of the object will be xf = Δx (as Δx = xf - xi).

Thus, if we put the position x at the horizontal axis and the force F at the vertical one, we will obtain the following graph:

Physics Tutorials: This image shows the graphical representation of work from a Physics perspective

Thus, it is obvious that Work represents the magnitude of the area under the Force vs Position graph (here, the area of a rectangle). This method for calculating the Work is particularly helpful if the force is not constant. In such cases, we simply calculate the abovementioned area and the result represents the amount of Work in Joules. Look at the example below:

Example

What is the work done by an object if the Force vs Position graph of the process is shown below?

Physics Tutorials: This image shows and example of the graphical representation of work from a Physics perspective

Solution

From the graph, we can see that the initial force used was 8N. This force constantly increased up to 24N during the 20m of displacement.

  1. One method for calculating the Work would be finding first the average force < F > = (8N + 24N) / 2 = 16N and then using the equation W = < F > ∙ Δx = 16N ∙ 20m = 320J.
  2. The other method (graph method) consists on calculating the area A of the trapezium formed by the graph and the two axes. Giving that the Area of trapezium is calculated by the equation:
Atrapezium = ( ( B + b ) × h ) ÷ 2

where B and b are the large and the small parallel sides of the trapezium respectively (here B = 24N and b = 8N) and h is its height (here h = 20m). Thus, substituting these values, we obtain

W = Atrapezium = ( 24N + 8N ) × 20m/2
= 32N × 20m/2
= 640J/2
= 320J

As you can see, the result obtained in both cases is the same.

You have reached the end of Physics lesson 5.1.4 The graphical representation of Work. There are 5 lessons in this physics tutorial covering Work and Energy. Types of Energy, you can access all the lessons from this tutorial below.

More Work and Energy. Types of Energy Lessons and Learning Resources

Work, Energy and Power Learning Material
Tutorial IDPhysics Tutorial TitleTutorialVideo
Tutorial
Revision
Notes
Revision
Questions
5.1Work and Energy. Types of Energy
Lesson IDPhysics Lesson TitleLessonVideo
Lesson
5.1.1What is Work in Physics?
5.1.2What is Energy?
5.1.3Calculation of Work in 2 and 3 Dimensions
5.1.4The graphical representation of Work
5.1.5How is Energy classified?

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